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Title: Some Berezin number inequalities for operator matrices (English)
Author: Bakherad, Mojtaba
Language: English
Journal: Czechoslovak Mathematical Journal
ISSN: 0011-4642 (print)
ISSN: 1572-9141 (online)
Volume: 68
Issue: 4
Year: 2018
Pages: 997-1009
Summary lang: English
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Category: math
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Summary: The Berezin symbol $\tilde {A}$ of an operator $A$ acting on the reproducing kernel Hilbert space ${\mathcal H}={\mathcal H}(\Omega )$ over some (nonempty) set is defined by $\tilde {A}(\lambda )=\langle A\hat {k}_{\lambda },\hat {k}_{\lambda }\rangle ,$ $\lambda \in \Omega $, where $\hat {k}_{\lambda }={{k}_{\lambda }}/{\|{k}_{\lambda }\|}$ is the normalized reproducing kernel of ${\mathcal H}$. The Berezin number of the operator $A$ is defined by ${\bf ber}(A)=\sup _{\lambda \in \Omega }|\tilde {A}(\lambda )|=\sup _{\lambda \in \Omega }|\langle A\hat {k}_{\lambda },\hat {k}_{\lambda }\rangle |$. Moreover, ${\bf ber}(A)\leq w(A)$ (numerical radius). We present some Berezin number inequalities. Among other inequalities, it is shown that if ${\bf T}=\left [\smallmatrix A&B\\ C&D \endmatrix \right ]\in {\mathbb B}({\mathcal H(\Omega _1)}\oplus {\mathcal H(\Omega _2)})$, then $$ {\bf ber}({\bf T}) \leq \frac {1}{2}({\bf ber}(A)+{\bf ber}(D))+\frac {1}{2}\sqrt {({\bf ber}(A)- {\bf ber}(D))^2+(\|B\|+\|C\|)^2}. $$ (English)
Keyword: reproducing kernel
Keyword: Berezin number
Keyword: numerical radius
Keyword: operator matrix
MSC: 15A60
MSC: 30E20
MSC: 47A12
MSC: 47A30
MSC: 47B15
MSC: 47B20
idZBL: Zbl 07031692
idMR: MR3881891
DOI: 10.21136/CMJ.2018.0048-17
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Date available: 2018-12-07T06:19:16Z
Last updated: 2021-01-04
Stable URL: http://hdl.handle.net/10338.dmlcz/147516
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